prove that triangle ABD Is congruent to triangle CDE and also
find the value of 'x'
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in triangle ABD and CDE. BD=ED (given)
BAD=ADC (ab||cd and ad is transversal ADC=DCE(ad||ce and cd is a transversal ) by ASA congruency ABD congruence CDE angle A equal to angle C (CPCT) hence ,2x+1=7 , 2x+1=7, 2x=7-1 ,2x=6 ,x=6÷2 , x=3
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