Question

Prove that triangle ADB and triangle ADC are similar.​

Answer 1

Answer:

In ∆ABD and ∆ADC,

AD=AD(Common)

Angle ADB=Angle ADC(90°)

Angle B=Angle C(45°)

Hence, ∆ABD and ∆ADC are similar...

Step-by-step explanation:

Angle A + Angle B + Angle C = 180°

90°+ Angle B + Angle C= 180°

Angle B + Angle C= 90°

There is a property of triangle that sum of two angles must be always greater than the third side. And it is only possible when other two angle is 45.

There are three properties of a right triangle when angle of right angled triangle is equal to 45 degrees.

Answer 2

Answer:

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