Question

prove that triangle dbc is an isosceles triangle.​

Answer 1

Answer:

To Prove: ∠ABD = ∠ACD. Proof: ∵ ABC is an isosceles triangle on the base BC. ⇒ ∠ABD = ∠ACD. ... Given: ∆ABC and ∆DBC are two isosceles triangles on the same base BC and vertices A and D are on the same side of BC