prove that triangle formed by joining the midpoints of the sides of a right angle triangle is also right angled
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Let the isosceles triangle be named as ABC where AB=BC and let D , E and F be the midpoints of sides AB, BC and CA respectively.
Now, F and E are midpoints => FE || AB and FE= 1/2 of AB.
Similarly, D and F are midpoints => DF || BC and DF=1/2 of BC = 1/2 of AB {Since AB=BC}
Therefore, in triangle DEF - EF=DF=1/2 of AB
Therefore triangle DEF is also isosceles.
Please refer the attachment for further clarification.
Hope This Helps :)
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