Question

prove that triangle PCD~ triangle PBC​

Answer 1

Step-by-step explanation:

angle d=angle c

angle cpd=angle bpc

hence,

triangle pcd is similar to triangle pbc

Answer 2

Answer:

in ∆PCD and ∆ PBL,

angle DCP=angle PBL

angle CDP=angle PLB

: ∆ PCD ~∆ PBL( AA similarity)

hence proved