Question

Prove that
trignometry class 10​

Answer 1

Answer:

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Answer 2

Q. Prove that tan A + sec A - 1 / tan A - sec A + 1 = 1 +sinA/cos A

Answer:

LHS = tan A + sec A - 1 / tan A - sec A + 1

= tan A + sec A - (sec²A - tan²A) / (tanA - secA + 1)

tan A + sec A -(secA + tan A)(secA - tanA) / (tanA - secA + 1) [a² - b² = (a+b)(a-b)]

= tan A + sec A (1 - (secA-tanA))/ (tanA - secA + 1) [Taking common]

= tan A + sec A (1 - secA + tanA) / (tanA - secA + 1)

= tan A + sec A

= sinA/cos A + 1/ cos A

= 1 + sinA/ cos A = RHS

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