Question

Prove that
Trigonometry​

Answer 1

Hi,

Consider LHS = 1/secA - tanA - 1/cosA

Multiplying by secA + tanA in the numerator and denominator of

first term,we get

=> secA + tanA/(secA +tanA)(secA - tanA) - 1/cosA

= secA + tanA - secA (Since sec²A - tan²A = 1)

= tanA

Adding and subtracting secA , we get

= secA + tanA - secA

= 1/cosA - (secA - tanA)

Now multiplying and dividing (secA - tanA) by (secA + tanA), we get

= 1/cosA - (sec²A - tan²A)/(secA + tanA)

= 1/ cosA - 1/secA + tanA

= R.H.S

Hence, Proved.

Hope, it helps !

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Answer 2

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Your answer is on attachment..

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