prove that trigonometry question
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tan3x = tan(2x+x)
=tan2x +tanx / 1-tan2x × tanx
=2 tanx/1-t^2 x + tanx /1- 2tanx*tanx/1-tan^ 2 x
=2tanx + tanx -tan ^3 x/tan^ 2 x-2tan ^2 x
=3tanx -tan^ 3 x/1-3tan ^2 x
Hope it's helpful!
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