Question

prove that:. trigonometry
${sin}^{6} +{ cos }^{6} = 1 - 3sin^{2} cos ^{2}$
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Answer 1

Answer:

prove that:. trigonometry

{sin}^{6} +{ cos }^{6} = 1 - 3sin^{2} cos ^{2}sin6+cos6=1−3sin2cos2