Prove that two distinct lines cannot have more than one point in common with diagram
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Proof
Let us consider that the two lines intersect in two distinct point P and Q.Thus we see that the two lines l and m pass through two distinct points P and Q.But this assumption clashes with the axiom. Given two distinct points, there is a uniqueline that passes through them.Hence our assumption is wrong that the two line can pass through two distinct points is wrong.Hence two distinct lines cannot have more than one point in common.
Let us consider that the two lines intersect in two distinct point P and Q.Thus we see that the two lines l and m pass through two distinct points P and Q.But this assumption clashes with the axiom. Given two distinct points, there is a uniqueline that passes through them.Hence our assumption is wrong that the two line can pass through two distinct points is wrong.Hence two distinct lines cannot have more than one point in common.
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