Question

prove that two triangles having same base and equal area lies between same parallels

Answer 1

Answer:

Step-by-step explanation: Two //gms ABCD and EFCD on same base DC and between same parallels AF and DC are given

Prove: ar(ABCD)=ar(EFCD)

Proof: In ΔADE and ΔBCF

∠DAE = ∠CBF (corresponding angles form AD║BC and transversal AF)

∠AED=∠BFC(corresponding angles from ED║FC and transversal AF)

also, AD=BC ( opposite sides of ║gm)

∴ΔADE≅ΔBCF BY ASA rule

∴ ar(ADE)=ar(BCF) (congruent figures have equal areas )

so, ar(ABCD) = ar(ADE)+ar(EDCB)

                      = ar(BCF)+ar(EFCB)

 ar(ABCD)     = ar(EFCD)

                                  HENCE PROVED

HOPE THIS WILL HELP YOU PLS MARK AS BRAINLIEST