prove that two triangles on same base and between the same parallel are equal in area.
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Answered by
5
yes it is true..
already the triangle have same base...
now,
parallel lines have same height..
and those triangles are in same parallels lines..
hence its height is also same..
A1 =1/2× b1×h1_____(1)
A2=1/2×b2×h2
: A2=1/2 × b1× h1___(2)
hence,
A1=A2......from equation 1 and 2
already the triangle have same base...
now,
parallel lines have same height..
and those triangles are in same parallels lines..
hence its height is also same..
A1 =1/2× b1×h1_____(1)
A2=1/2×b2×h2
: A2=1/2 × b1× h1___(2)
hence,
A1=A2......from equation 1 and 2
Answered by
11
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