Prove that under root 1+CosA/1-CosA = CosecA +CotA
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Answered by
217
Hi ,
LHS = sqrt [ ( 1 + cos A ) / ( 1 - cos A )
Multiply numerator and denominator with ( 1 + cos A )
= sqrt [ ( 1 + cos A ) ( 1 + cos A ) / ( 1 - cos A ) ( 1 + cos A ) ]
= sqrt [ ( 1 + cos A ) ^2 / ( 1^2 - cos ^2 A ) ]
[ since ( a + b ) ( a - b ) = a^2 - b ^2 ]
= sqrt [ ( 1 + cos A ) ^2 / ( sin ^2 A ) ]
= ( 1 + cos A ) / sin A
= ( 1 / sin A ) + ( cos A / sin A )
= cosec A + cot A
= RHS
I hope this helps you.
****
LHS = sqrt [ ( 1 + cos A ) / ( 1 - cos A )
Multiply numerator and denominator with ( 1 + cos A )
= sqrt [ ( 1 + cos A ) ( 1 + cos A ) / ( 1 - cos A ) ( 1 + cos A ) ]
= sqrt [ ( 1 + cos A ) ^2 / ( 1^2 - cos ^2 A ) ]
[ since ( a + b ) ( a - b ) = a^2 - b ^2 ]
= sqrt [ ( 1 + cos A ) ^2 / ( sin ^2 A ) ]
= ( 1 + cos A ) / sin A
= ( 1 / sin A ) + ( cos A / sin A )
= cosec A + cot A
= RHS
I hope this helps you.
****
Answered by
88
Step-by-step explanation:
hey mate this may helps you
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