Math, asked by mam1alsatyar4eddy, 1 year ago

Prove that under root 1+CosA/1-CosA = CosecA +CotA

Answers

Answered by mysticd
217
Hi ,

LHS = sqrt [ ( 1 + cos A ) / ( 1 - cos A )

Multiply numerator and denominator with ( 1 + cos A )

= sqrt [ ( 1 + cos A ) ( 1 + cos A ) / ( 1 - cos A ) ( 1 + cos A ) ]

= sqrt [ ( 1 + cos A ) ^2 / ( 1^2 - cos ^2 A ) ]

[ since ( a + b ) ( a - b ) = a^2 - b ^2 ]

= sqrt [ ( 1 + cos A ) ^2 / ( sin ^2 A ) ]

= ( 1 + cos A ) / sin A

= ( 1 / sin A ) + ( cos A / sin A )

= cosec A + cot A

= RHS

I hope this helps you.

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Answered by pallavigowda59
88

Step-by-step explanation:

hey mate this may helps you

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