Question

prove that (under root 2 - 3) cube is irrational​

Answer 1

Answer:

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Step-by-step explanation:

By contradiction, say 2–√3 is rational

then 2–√3=ab in the lowest form, where a,b∈Z,b≠0

2b3=a3

b3=a32

therefore, a3 is even

therefore, 2∣a3,

therefore, 2∣a

∃k∈Z,a=2k

sub in: 2b3=(2k)3

b3=4k3, therefore 2|b

Contradiction, a and b have common factor of two

Answer 2

Answer:

where ever route comes and it can't be simplified like route2 is 1.4567. something OK so it is irrational