Question

prove that under root 2 by 7 is an irrational number​

Answer 1

Answer:

your answer is here !

Step-by-step explanation:

Hi friend, Here's the required answer:-

Let us assume that 2/√7 is rational number.

2/√7= 2/√7 × (√7/√7)= 2√7/7. ( Rationalising)

Now, 2√7/7 = p/q ( as rational no. can be written in the form of p/q=)

2√7= 7p/q

√7= 7p/2q

Here LHS is irrational but RHS is rational.

This contradicts the statement.

Our assumption is wrong.

2/ √7 is an irrational number.

Hope this helps you...

follow me !

Answer 2

Answer:

Verified Answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but Verified Answers are the finest of the finest.

Hi friend, Here's the required answer:-

Let us assume that 2/√7 is rational number.

2/√7= 2/√7 × (√7/√7)= 2√7/7. ( Rationalising)

Now, 2√7/7 = p/q ( as rational no. can be written in the form of p/q=)

2√7= 7p/q

√7= 7p/2q

Here LHS is irrational but RHS is rational.

This contradicts the statement.

Our assumption is wrong.

2/ √7 is an irrational number.

Hope this helps