Question

prove that under root 3 + under root 5 is a irrational number​

Answer 1

Hope It Helps You Mate

Mark as branliest if it helped you

Answer 2

Answer:

To prove

$\sqrt{3 + \sqrt{5} }$

is an irrational number lets. contradicts that it is a rational number so it can be writtin in the form of p/q where q is not =0 ,p and q are co prime so it can we written as

$\frac{p}{q } = \sqrt{3 + 5}$

$\frac{p}{q} - \sqrt{3 } = \sqrt{5}$

$\frac{p - \sqrt{3q} }{q} = \sqrt{5}$

Here

$\frac{p - \sqrt{3q} }{q}$

is rational but it is equal to √5 which is and irrational number so our contradiction is wrong √3+√5 is and irrational number