prove that under root 5 is irrational number
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Step-by-step explanation:
please refer to book example 4 or 5 of class10 same question :)
Answered by
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Answer:
let √5 be rational
5=a^2/b^2
5b^2=a^2
therefore a is divisible by 5
now,
a=5c
therefore
25c^2=5b^2
b^2=5c^2
therefore b is also divisible by 5
this contradicts our assumption
thus √5 is an irrational no.
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