Question

prove that under rut 3 is an irrational number​

Answer 1

Step-by-step explanation:

Then √3 = p/q, where p, q are the integers i.e., p, q ∈ Z and co-primes, i.e., GCD (p,q) = 1. Here 3 is the prime number that divides p2, then 3 divides p and thus 3 is a factor of p. ... Therefore, the root of 3 is irrational.

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Answer 2

Answer:

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