Question

prove that using the identity
sec ²θ = 1 + tan² θ

sin θ - cos θ + 1 / sin θ + cos θ - 1
== 1 / sec θ - tan θ​

Answer 1

Answer:

3Sin(theeta) = 4Cos(theeta)

Sin(theeta)/Cos(theeta) = 4/3

Tan(theeta) = 4/3

And

Sec(theeta) = Square Root [ 1+Tan^2 (theeta)]

Sec(theeta) = Square Root [ 1+ (4/3)^2]

Sec(theeta) = Square Root [ 1+16/9]

Sec(theeta) = Square Root [ 9+16 /9]

Sec(theeta) = Square Root [ 25/9]

Sec(theeta) = +-(5/3)

So, l hope it's help you