Question

prove that:
V^2 - U^2 = 2as​

Answer 1

Explanation:

From 1st equation of motion,

V = U + AT

Therfore, V - U = AT

We know that

S = (U + V / 2 )×T

∴ S/T = U + V / 2

∴U + V = 2×S/T

∴ U + V = 2S / T

So Substituting eq1 and eq2,

(V - U ) (V + U ) = AT ×2S/T

∴V² - U² = 2AS.

Answer 2

Explanation:

The first equation of motion is v = u + at

v - u = at –-–-–-–-–-–-–1

Average velocity = s/t-–-–-–-–-–2

Average velocity = u+v/2-–-–-–-–-–3

From equation 2 and 3 we get ,

u+v/2 = s/t-–-–-–-–-–-–-–4

Multiplying equation 1 and equation 4 we get ,

(v-u)(v+u) = at × 2s / t

(v-u)(v+u) = 2as. [a^2-b^2 = (a+b)(a-b)]

v^2 - u^2 =2as

HOPE IT HELPS YOU!!!!