prove that v^2=u^=2as
Answers
Explanation:
PQ=
d
2
−(r
1
−r
2
)
2
PQ=
8
2
−2
2
PQ=7.75cm
Draw a line segment AB=15cm. Draw circle C1 with radius 4cm and centre as A. Draw circle C2 with radius 2cm and centre B
Draw circle C3 with radius (R
1
−R
2
=4−2=2cm and centre A. B is the external point to circle C3. Draw perpendicular bisector of AB and mark its midpoint M
With M as centre and AM as radius construct a circle C4
C4 cuts C3 at two points E and F. Join AE and AF
Extend AE to meet C1 at P and AF to meet C1 at R
Draw BQ∥AP and BS∥AR
Join PQ and RS. PQ and RS are required direct tangents.
Answer:
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Explanation:
Answer:
We will use both of the equations of motion to reach the third equation of motion. This will require a bit of algebra.
S=ut+
2
1
at
2
andv=u+at, include the time variant t
There will be some situations when we do not have any information about time and so it would be a good idea to derive an equation that does not have a t term.
To do this, we rearrange our first equation to get
t=
a
v−u
and use this to replace t wherever it appears in the second equation. So
S=ut+
2
1
at
2
becomes,
S=u(
a
v−u
)+
2
1
a(
a
v−u
)
2
⇒2aS=2u(v−u)+(v−u)
2
⇒2aS=2uv−2u
2
−v
2
−2uv−u
2
⇒2aS=v
2
−u
2
⇒v
2
=u
2
+2aS