prove that V2=U2+2as
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Explanation:
We know that,
dv⃗dt=a⃗
Multiplying and dividing LHS by ds⃗
⟹dv⃗ds⃗ds⃗dt=a⃗
We replace ds⃗dt with v⃗ to get
v⃗dv⃗ds⃗=a⃗
⟹v⃗dv=a⃗ds
We know that at S=0,V=u and at S=s,V=v ,
Integrating both sides with appropriate limits:
⟹∫vuvdv=∫s0ads
⟹v22|vu=as|s0
⟹v22−u22=a(s−0)
⟹v2−u22=as
⟹v2−u2=2as
⟹v2=u2+2as
Or more appropriately,
v⃗⋅v⃗=u⃗⋅u⃗+2a⃗⋅s⃗
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