Prove that V6 is irrational.
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Let us assume that 6 is rational number.
Then it can be represented as fraction of two integers.
Let the lowest terms representation be: 6 = a/b where b is not equal to zero .
* Note that this representation is in lowest terms and hence, a and b have no common factor.
a² = 6b²
From above a² is even. If a² is even, then 'a' should also be even.
⟹a=2c
→ 4c² = 6b²
→ 2c² = 3b²
From above 3b² is even. If 3b² is even, then b² should also be even and again 'b' is even.
But a and b were in lowest form and both cannot be even.
Hence, assumption was wrong .
Thus , V6 is an irrational number.
HOPE IT HELPS ❗.
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