Question

Prove that value of sin^2x + cosec^2x cannot be less than 2

Answer 1

if we substitute 0 in X we get

sin^2×0+cosec^2×0

which is equal to sin^0+cosec^0

anything raised to 0 is 1 therefore

we get 1+1 =2 Hence if we increase the value of X from 0 onwards the value always will differ if theta is given but it will not be smaller than 2