Question

prove that vector A.vectorA=A^2 and vector A×VectorA=0​

Answer 1

Answer:

Let A.(AxB) = 0

As , AxB = AB sinФ n

AB sinФ n is a vector which is perpendicular to the plane having A vector and B vector which implies that it is also perpendicular to A vector .

As we know dot product of two vectors is zero.

Thus , we can say that

A.(AxB) = 0

Explanation:

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