Question

Prove that weber volt × second

Answer 1

The SI unit for weber is (m^2 x kg)/(s^2 x A).
One volt equals to one joule/coulomb,
which is : W/Q.
Now, the SI unit for volt is (m^2 x kg)/(s^3 x A). 
now volt x sec = (m^2 x kg x s)/(s^3 x A)
volt x sec = (m^2 x kg)/(s^2 x A)
volt x sec​ =  weber