Physics, asked by ABSiddique, 1 year ago

Prove that weight of a substance on Moon is 1/6 of Earth​

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Answered by alkasagar4
2

Answer:

Gravitation

Explanation:

Given that the mass of the earth is 100 times the mass of the moon and its radius is 4 times that of the moon. Weight of the object on earth is the force with which the earth attracts the object towards it.

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Answered by sanketdolas
1

Answer:

Suppose a body of mass "m" and its weight on the moon is Wm (where W is the weight and "m" is the moon;which means weight on the moon).Mass of the moon is "M"

and its radius is "R"

Weight of an object on the moon = "F"(Force)with which the moon pulls.

Wm = GM*m/r2

Weight of the same object on the earth is We(where W is the weight and "e" is the earth;which means weight on the earth).

Mass of the earth is 100 times of that of the moon.

Radius of the moon = R

Radius of the Earth = 4R

Weight of the object on the moon =

We = G100M*m/(4R)2(Pronounced 4 R square)

We = G100M*m/(16R)2(Pronounced 16 R square)

Wm/We = G * M * m * 16R2/R2 * g * 100M * m

=16/100

Wm/We = 16/100 =1/6

Weight on the moon is 1/6 weight on the earth.(Hence Derived

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