Question

Prove that when a body is thrown vertically upward its time of ascent is equal to descent.

Answer 1

Answer:

you can calculate it by motion equation

Explanation:

let we throw a object with velocity "v" and covered distance "s" in time "t"

during ascent time we have,

v = u - at ( velocity decreses so A is taken negative)

then, t = u - v / a

and finally V is zero at a point.

hence, t = u/a

and during descent

V = u + at ( because "a" is taken as positive)

and u is equal to v of ascent velocity

so u is zero

hence V = 0 + at , V = at and t = v/a

interesting is velocity with which object is thrown is equal to velocity with it stike ground during descent.

so "u" of ascent is equal to "v" of descent.

put it on equation.

we have t = v/a and t = u/a

we have v=u

then, t of ascent = u/a

and "t" of descent = u/a also.

hence it has prooved

time of going at the highest point is equal to the time taken to come on its original place