Prove that when a body thrown vertically upward its time of ascent is equal to descent.
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total project v^2 = u^2 +2as
v^2 = u^2 +2(-g)0
v^2 =u^2
0= v^2 - u^2
0= (v-u)(v + u)
v = u//-----(1)
upward doward movement
v = u +at v = u + at
0=u -gt v = 0 +gt'
u/g =t u = 0 +gt'{equation 1 v= u}
t' =u/g
accordingly t =t'
accordingly
body thrown vertically upward its time of ascent is equal to descent.
v^2 = u^2 +2(-g)0
v^2 =u^2
0= v^2 - u^2
0= (v-u)(v + u)
v = u//-----(1)
upward doward movement
v = u +at v = u + at
0=u -gt v = 0 +gt'
u/g =t u = 0 +gt'{equation 1 v= u}
t' =u/g
accordingly t =t'
accordingly
body thrown vertically upward its time of ascent is equal to descent.
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