prove that: when the angle is projected at an angle of 45° with the horizontal distance travelled by it is maximum.
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Explanation:
If a particle is projected at fixed speed, it will travel the furthest horizontal distance if it is projected at an angle of 45° to the horizontal. This is because the maximum sin2a can be is 1 and sin2a = 1 when a = 45°. The velocity of the particle at any time can be calculated from the equation v = u + at.
Answered by
1
Explanation:
If a particle is projected at fixed speed, it will travel the furthest horizontal distance if it is projected at an angle of 45° to the horizontal. This is because the maximum sin2a can be is 1 and sin2a = 1 when a = 45°. The velocity of the particle at any time can be calculated from the equation v = u + at.
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