prove that (x^1÷a-b)^1÷a-c × (x^1÷b-c)^1÷b-a × (x^1÷c-a)^1÷c-b=1
Attachments:
Answers
Answered by
3
please see the attachment
Attachments:
Answered by
0
Step-by-step explanation:
Here's The Solution
Attachment
Attachments:
Similar questions