Question

↪Prove that, (x+1) is a factor of equations X²+3x+2=0.

✔✔✔✔✔✔✔✔✔✔✔✔✔✔​

Answer 1

$\huge\boxed{\fcolorbox{cyan}{Red}{Solution:-}}$.

↪Given equations .

♠X²+3x+2=0.

↪if (x+1) is a factor of this equations , so x= -1, is exits this equations .

↪Keep x= -2,

▶(-2)²+3(-2)+2=0.

=> 4-6+2=0.

=>6-6=0.

=>0=0.

✔Thats proved .

Answer 2

Answer:

According to The Remainder Theorem (x + a) is a factor of polynomial p(x) if and only if P(-a) = 0.

To check if (x + 1) is a factor of x² + 3x + 2 = 0 you have to check p(-1) = 0.

P(-1) = (-1)² + 3(-1) + 2

P(-1) = 1 - 3 + 2

P(-1) = -2 + 2

P(-1) = 0

P(-1) is Zero, so (x + 1) is the factor of P(x).