Question

prove that x+1 is a factor of x^99+1 and x^100-1 plz show full calculations ill mark as brainliest

Answer 1

Answer:

P(X) = X^99-1

P(Y) = X^100-1

ACCORDING TO THE FACTOR THEREOM IF X-1 IS THE FACTOR OF P(X) AND P(Y) THEN THEN P(1) = 0

P(X) = X^99-1

P(1) = (1)^99-1

P(1) = 1-1

P(1) = 0

SO P(1) BECOME ZERO SO X-1 IS THE FACTOR OF P(X)

P(Y) = X^100-1

P(1) = (1)^100-1

P(1) = 1-1

P(1) = 0

SO P(1) BECOME ZERO SO X-1 IS THE FACTOR OF P

hope it's help you

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