prove that x+1 is a factor of x^99+1 and x^100-1 plz show full calculations ill mark as brainliest
Answers
Answered by
4
Answer:
P(X) = X^99-1
P(Y) = X^100-1
ACCORDING TO THE FACTOR THEREOM IF X-1 IS THE FACTOR OF P(X) AND P(Y) THEN THEN P(1) = 0
P(X) = X^99-1
P(1) = (1)^99-1
P(1) = 1-1
P(1) = 0
SO P(1) BECOME ZERO SO X-1 IS THE FACTOR OF P(X)
P(Y) = X^100-1
P(1) = (1)^100-1
P(1) = 1-1
P(1) = 0
SO P(1) BECOME ZERO SO X-1 IS THE FACTOR OF P
hope it's help you
now mark as brainliest
Similar questions
Physics,
4 months ago
History,
8 months ago
Computer Science,
8 months ago
Math,
11 months ago
CBSE BOARD X,
11 months ago