prove that x-1 is a factor of x³-6x²+11x-6
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if x-1 is a factor then substitute the value 1 in equation x^3-6x^2+11x-6 as the remainder is zero so x-1 is a factor
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if x-1 is the factor of this equation this means that if x=1 ( as x-1=0 , so x=1) then the polynomial will give the answer as zero .
so by putting we will get --- 1 - 6 + 11 - 6 = 0
therefore x-1 is a fator of this polynomial
so by putting we will get --- 1 - 6 + 11 - 6 = 0
therefore x-1 is a fator of this polynomial
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