Prove that : √x-1y×√y-1z×√z-1x=1
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x^2 + y^2 + 6x + 8y = 0 and x^2 + y^2 - 4x - 6y - 12 = 0 are the equation of the two circle Equation of one of their common tangent isFor real
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sbidkta
sorry bro i dont know the answer
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