Prove that x^2+2x+8 has no zero
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A quadratic equation of the form ax² + bx + c = 0 has no real zeroes when discriminant of equation is < 0
⇒⇒ b² - 4ac < 0
Comparing x² + 2x + 3 = 0 with ax² + bx + c=0
⟹ a=1, b=2, c=3
= b² - 4ac
= 2² - 4×3
⟹ 4 - 12 = -8 < 0
As discriminant is less than zero x² + 2x + 3 = 0 will have no real roots.
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