Question

prove that X + 2 is a factor of 6 x cube + 19 X square + 16 X + 4 by using the factor theorem and also factorise 6 x cube + 19 X square + 16 X + 4 how to solve​

Answer 1

Answer:

Step-by-step explanation:

By using the Factor theorem, we will replace x = -2 since, x + 2 = 0.

⇒ 6x³ + 19x² + 16x + 4

= 6(-2)³ + 19(-2)² + 16(-2) + 4

= (-48) + 76 + (-32) + 4

= 0

which proves that (x + 2) is a factor of 6x³ + 19x² + 16x + 4

Factorization.

6x³ + 19x² + 16x + 4 = 6x³ + 12x² + 7x² + 14x + 2x + 4

= 6x²(x + 2) + 7x(x + 2) + 2(x + 2)

= (6x² + 7x + 2)(x + 2)

= (3x(2x + 1) + 2(2x + 1))(x + 2)

= (3x + 2) ( 2x + 1) (x + 2)

Hope it Helps!!

Answer 2

Step-by-step explanation:

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