prove that (x-2)is a factor of
(x³- 8)
Answers
Answered by
0
Hey user here is your solution....
x-2=0
So,
x=2
Now put this in given equation
(x^3-8)
◆(2)^3-8
◆8-8=0
●so here answer is 0 ,so (x-2) is factor of (x^3-8)
Hope it helps you☺️
x-2=0
So,
x=2
Now put this in given equation
(x^3-8)
◆(2)^3-8
◆8-8=0
●so here answer is 0 ,so (x-2) is factor of (x^3-8)
Hope it helps you☺️
Answered by
0
Hey
Here is your answer,
X-2 =0
X = 2
When we substitute the value of x in the equation , it must result in 0
( x^3 - 8 ) = 0
2^3 -8=0
8-8=0
Hence proved.
Hope it helps you!
Here is your answer,
X-2 =0
X = 2
When we substitute the value of x in the equation , it must result in 0
( x^3 - 8 ) = 0
2^3 -8=0
8-8=0
Hence proved.
Hope it helps you!
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