Question

Prove that (x-2),(x+3)and(x-4) are factors of the polymial:p(x)=x³-3x²-10x+24​

Answer 1

Answer:

(x-2) =0

x=2

x+3=0

x=-3

x-4=0

x=4

Step-by-step explanation:

p(x)=x cube -3x^-10x+24

p(2) =(2) cube-3(2) ^+10(2) +24

=8-12-20+24

=0

p(-3) =(-3)cube-3(-3) ^-10(-3) +24

=-27-27+30+24

=0

p(4) =(4) cube-3(4) ^-10(4) +24

=64-48-40+24

=0

hence proved