prove that x^2-x is divisible by 2 for every positive integer x
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X2-x
(1)put x= 1
(1)2-1= 0 divisible by 2
(2)put x= 2
(2)2-2= 4-2= 2 divisible by 2
(3)put = x= 3
(3)2-3= 9-3= 6 divisible by 2
Therefore x2-x is divisible by 2 for every +ve integer x.
(1)put x= 1
(1)2-1= 0 divisible by 2
(2)put x= 2
(2)2-2= 4-2= 2 divisible by 2
(3)put = x= 3
(3)2-3= 9-3= 6 divisible by 2
Therefore x2-x is divisible by 2 for every +ve integer x.
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