prove that (x-3) is a factor of the polynomial x^3 - 3x^2 + 4x - 12
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x^3-3x^2+4x-12=0
x^2(x-3)+4x -12=0
x^2(x-3)+4(x-3)=0
(x^2+4)(x-3)=0
x^2+4=0 and x-3=0
x^2=-4 and x=3
x= square root of -4 and x=3
x= square root of -4 is not possible and x=3
Your answer is x-3
x^2(x-3)+4x -12=0
x^2(x-3)+4(x-3)=0
(x^2+4)(x-3)=0
x^2+4=0 and x-3=0
x^2=-4 and x=3
x= square root of -4 and x=3
x= square root of -4 is not possible and x=3
Your answer is x-3
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