Question

prove that (x-5) is a factor of 2x²-x- 45. hence factorize 2x²-x-45 completely. pls answer ​

Answer 1

Answer:

I HOPE IT HELPED YOU...

Answer 2

Answer:

Zeroes = 9/2 and 5.

Step-by-step explanation:

To prove : (x - 5) is the factor of p(x).

Proof :

Since the given equation is a quadratic equation, thus there will be two values of x. According to the question on value of x must be equal to 5. This is because since,

x - 5 = 0 (to prove)

x = 5 (to prove)

p(x) = 2x²-x- 45

By splitting the middle term, we get

=>2x^2 - 10x + 9x - 45=0

=> 2x(x-5)-9(x-5)=0

=> (2x - 9)•(x - 5) = 0

For the values of x,

CASE I :

(2x - 9) = 0

=> 2x = 9

=> x = 9/2 ...... (i)

CASE II :

(x - 5) = 0

=> x = 5 ..... (ii)

From equation (ii) we prove, that (x - 5) is the factor of 2x²-x- 45.

Now from equation (i) and (ii), we get,

x = 9/2 , 5

Hence, zeroes of the 2x²-x- 45 are : 9/2 and 5.