Prove that
(x^a+b)^2 (x^b+c)^2 (x^c+a)^2/(x^a x^b x^c) = 1
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Answered by
7
Step-by-step explanation:
(x^a+b)^2 (x^b+c)^2 (x^c+a)^2/(x^a x^b x^c) = 1
=x2a+2b × 2b+2c × 2c+2a×a+b+ c⁴
= x2a+2b+2b +2c+2c+2a×4a+4b+4c
=x4a+4b+4c×4a+4b+4c
=x4a+4b+4c-4a-4b-4c
=X
Where,
X=0
Hope it will help you
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