Question

Prove that x^a (b-c)/x^b(a-c)÷(x^b/x^a)^c

Answer 1

Hi ,

x^a(b-c)/x^b(a-c) = ( x^b/x^a)^c

LHS = x^a(b-c)/x^b(a-c)

= [ x^(ab-ac)/x^(ab-bc) ]

= x^ab-ac-ab+bc

= x^-ac + bc

= x^ bc - ac

= [ x^( b - a )c ]

= [ x^( b - a ) ]^c

= [ x^b/x^a ]^c

= RHS

I hope this helps you.

: )