prove that (x^a/x^b) ^c × (x^b/x^c) ^a ×(x^c/x^a) ^b =1
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Given,
=( x b x a ) c ×( x c x b ) a ×( x a x c ) b
=(x a−b ) c ×(x b−c ) a×(x c−a ) b
=x ac−bc ×x ab−bc ×x bc−ab
=x ac−bc+ab−bc+bc−ab
=x 0
=1
[henceproved]
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