Question

prove that x minus 1 is a factor of x cube minus one​

Answer 1

HOPE IT HELPS :

Factor :

Generally Factor is used to mean a number that can be multiplied or divided to produce a given number

Solution :

$=> x^{3} - 1$

$=> x^{3} - 1^{3}$

Using identity of $(a^{3}-b^{3})$ we get that

$=>(x-1)(x^{2} + 1 + x )$

Hence the expression can easily be divide by (x-1) hence it is a factor .

STAY HOME STAY SAFE

x JOKER ALWAYS x

Answer 2

Answer:

No ,Becuse x³-1 ≠0

Step-by-step explanation:

x-1

x-1=0

x=1

Put the value in x³-1

1³-1

1+1=2

therefore it is not equal to 0 proof