Question

prove that X square + 6 X + 15 has no real zero

Answer 1

Discriminant = b² - 4ac

Here,
a = 1
b = 6
c = 15


Discriminant = b² - 4ac

=> (6)² - 4(1×15)

=> 36 - 60

=> -24




As - 24<0 ,the given equation does not any real root.


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Answer 2

P (x) = x^2 + 6x + 15

Discriminent = b^2 - 4ac

= (6)^2 - 4(1)(15)

= 36 - 60

= - 24

Discriminent is negative, so the roots are imaginary.