prove that (x+ y)2 + (x - y )2 = 2 (x2 + y2)
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Yes here LHS = RHS
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Answer:
identities:
(a+b)² = a² + 2ab + b²
(a-b)² = a² - 2ab + b²
(x+y)² + (x-y)²
= x² + 2ab + y² + x² - 2ab + y² = 2 [using the above mentioned identities]
= x² + y² + x² + y² [ + 2ab and - 2ab cancel each other ]
= 2x² + 2y²
= 2 (x² + y²)
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