prove that (x+y)³-(x-y)³-6y(x²-y²)=8y³
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x^3 + y^3 - 3 x. y^2 -3 x^2.y - x^3 + y^3 + 3x.y^2 - 3 X^2 .Y - 6 YX^2 + 6 y^3
=8 y ^3
=8 y ^3
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Consider,
can be rewritten as
We know,
So, using this algebraic identity, we get
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