Prove that (x+y)³+(y+z)³+(z+x)³-3(x+y)(y+z)(z+x)=2(x³+y³+z³).
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I want to tell u that solve all cube and u will get answer
(a+b)^3=a^3+b^3+3ab (a+b)
(a+b)^3=a^3+b^3+3ab (a+b)
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you could get this answer by opening the brackets .then R.H.S=L.H.S. PROVED
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